Algebra Lessons: 5 Steps For Success

Algebra Lessons: 5 Steps For Success
By Rob A. Jackson

Your teenager's education foundation and learning begins with algebra. The subject is relevant for growing upon other math fields as well as several other fields which include sciences, architecture, and engineering. As moms and dads, it is imperative that your youngster understands algebra from the very start to ensure that an academic foundation is built for future math disciplines. The following are five helpful strategies to help your daughter or son conquer this important subject matter.

In any standardized examinations, such as the SAT or ACT, the most common topic tested is algebra. For that reason, it is imperative that your child have a solid understanding of algebra if you want your child to be accepted into a good university. Basic sub-topics like fractions and various other functions are regularly examined. Consequently, your child will not score very well if your child does not fully grasp these concepts.

Find an algebra instructor who can guide your son or daughter with preparation and studying for assessments. A tutor will help your child pay attention as well as help with comprehension outside of the classroom. Ensure that the algebra tutor you select for tutoring is experienced, trained, and provides a background of references for teaching in algebra. Ask the tough questions. Is the tutor a college or university graduate? Does he or she have proficiency in a math or a math-intensive field?

Without a doubt, algebra will occupy much time for your youngster out of school, despite the capability or intelligence of your daughter or son. For this reason, it is really important that you command your daughter or son to invest significant time in accomplishing his or her assignments. Seek the advice of your daughter or son's instructor and inquire how long your youngster ought to be investing on his or her algebra assignments. Design study time for your teenager based on this recommendation.

Some children learn better in a private setting, so discover what setting your son or daughter learns algebra best. For that reason, the classroom surroundings may not be the most advantageous to your son or daughter's learning. While the classroom is obviously necessary, as a parent, you must understand your teenager's learning patterns and employ the services of a tutor if that is necessary. Since algebra lessons are typically not expensive, you can get the help your teenager needs while remaining in budget.

Ensure that you are familiar with your son or daughter's algebra textbook. Indeed, you likely have not opened a textbook in quite a few years; nonetheless, it's necessary that you become versed in the subject matter all over again so when your kid requests help, you can provide it. At the same time, if you do not fully grasp the concepts your child is learning, get help from your child's teacher after class or do not hesitate to retain the services of a tutor.

Unquestionably, algebra is a tricky topic area for your son or daughter to comprehend. As a result, it's a necessary facet to his or her educational background that is going to serve as a cornerstone to his or her future success. Whether for the SAT or ACT or to receive an "A" in a class, ensure your kid is competent in algebra by acquiring an algebra tutor. You will be glad, both personally and academically, you did!

Rob is a teacher, tutor, and math enthusiast. Learn more about algebra tutoring at San Diego algebra lessons.

Article Source: http://EzineArticles.com/?expert=Rob_A._Jackson
http://EzineArticles.com/?Algebra-Lessons:-5-Steps-For-Success&id=7444060

Two Linear Equations in Two Variables

Two Linear Equations in Two Variables
By Andrew Holyk

Suppose you want to solve a system of two linear equations in two variables.

I will discuss elimination method.

So, you have following general system:

ax+by=c

dx+ey=f

Elimination method works as follows: express x (or y) from first expression and plug result into second.

I will express x from first:

x=(c-by)/a

Now, plug result into second:

d(c-by)/a+ey=f

dc/a-by/a+ey=f

y(e-b/a)=f-dc/a

y=(f-dc/a)/(e-b/a)

Now, x=(c-by)/a=(c-b(f-dc/a)/(e-b/a))/a

A bit messy, right?

But on practice it is more clear.

Example 1. Solve the system

3x+2y=12

4x+5y=23

Solution.

Express x from first equation: x=(12-2y)/3

Now, plug this result into second:

4*(12-2y)/3+5y=23

Multiply both sides of equation by 3:

4(12-2y)+15y=69

48-8y+15y=69

7y+48=69

7y=21

y=3

Now, x=(12-2y)/3=(12-2*3)/3=2

Thus, x=2 and y=3

Example 2. Solve the system

x-4y=-3

y-3x=-2

Solution.

Actually it doesn't matter from which equation to express variable and what variable to express.

Let's express y from second equation:

y=3x-2

Plug this result into first:

x-4(3x-2)=-3

x-12x+8=-3

-11x=-11

x=1

Finally, y=3x-2=3*1-2=1

So, x=1 and y=1.

Probably, you know that system of two linear equations in two variables has either one solution or no solution or infinitely many solutions.

Let's see how elimination method works when we have two special cases: no solution or infinitely many solutions.

Example 3. Solve the system

2x+3y=2

4x+6y=4

Solution.

From first equation x=(2-3y)/2

Plugging this in first yields:

4(2-3y)/2+6y=4

2(2-3y)+6y=4

4-6y+6y=4

4=4

Wow! All variables have canceled out.

Since 4=4 is correct equality then this system has infinitely many solutions.

Example 4. Solve the system

2x+3y=1

4x+6y=4

Solution.

From first equation x=(1-3y)/2

Plugging this in first yields:

4(1-3y)/2+6y=4

2(1-3y)+6y=4

2-6y+6y=4

2=4

Again all variables have canceled out.

But, since 2=4 is incorrect equality then this system has no solution.

Geometrically all above three cases have following meaning:

1. System has one solution: lines intersect at one point.
2. System has no solution: lines are parallel and don't coincide.
3. System has infinitely many solutions: lines coincide.

More math notes at http://www.emathhelp.net

Article Source: http://EzineArticles.com/?expert=Andrew_Holyk
http://EzineArticles.com/?Two-Linear-Equations-in-Two-Variables&id=7695549

Solve Math Questions Online and Enhance Your Skill

Solve Math Questions Online and Enhance Your Skill
By Sandy D'Souza

Rigorous practice is the main key to achieve success in math. Research suggests that most students do not spend enough time to practice math on a regular basis. The reasons can be varied, from disinterest to inefficiency. The fact is that when students do not understand the topic properly, they lose their interest and end up disappointed due to poor grades in exams. To solve a mathematical problem accurately, students need to be completely involved. The process of solving a mathematical problem demands several sequential steps. First, students need to find the method involved in the problem. Second, they need to apply the right formula to get the correct solution. Third, they can find the alternate method to solve the same problem.

Practice math questions and answers

To make each learning session more effective, students should practice various problems on the same topic. This gives students more clarity on each topic. Additionally, they can easily find out their learning problems and take required steps to overcome these. However, students have a tendency to stick to a topic which is easy to solve. Experts suggest that they should change this habit and try to solve all kinds of problems to get familiar with the entire curriculum. To become an ace in math, students need to practice math regularly.

Several websites offer math help. When a student feels that he/she does not understand the math concepts thoroughly in a classroom environment and cannot cover the syllabus on time, they can opt for online math assistance. This learning process gives them better understanding of each topic. Most importantly, with this service, students can choose grades, topics and level of difficulties accordance to their preference. They can choose the worksheet which they want to work on. Online math help is fast and easy to use for students. They can find instant solutions related to any topic including algebra, calculus, etc. Students can also use some math quizzes and games available on those websites to make math interesting.

Take online help to solve tricky math problems

Students need to have patience to solve any tricky math problem accurately. However, most students do not practice math regularly and try to memorize some easy methods to solve all problems in exams. This is definitely a wrong technique to prepare for the math exam. Any student can learn math by following step-by-step and detailed explanations. Students can have this facility with online math help. They can choose their preferred tutor along with suitable timings.

Online math help is few steps away from students. Students can access online help anytime and from any place. It enables a good number of students to score well in exams. This innovative learning process also enhances students' confidence. In short, by using this online service, students get adequate learning help in a convenient and comfortable way.

To improve your mathematical skills students can take extra care in some parts like more practice and they can also take help of math tutors or with online math help and also the most important thing is working on the assignments given in regular class sessions. This makes you score good marks and enhances your skills.

Article Source: http://EzineArticles.com/?expert=Sandy_D'Souza
http://EzineArticles.com/?Solve-Math-Questions-Online-and-Enhance-Your-Skill&id=7689217

Sample of Basic Algebra Test

Author: Matthew David

Sample of Basic Algebra Test

Introduction to algebra:

Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics. (Source: Wikipedia)

In this topic we are discuss about Sample of Basic Algebra Test  introduction and Sample of Basic Algebra Test examples

Sample of Basic Algebra Test Questions:

1) Solve the add sum of 4x4 – x2 + 2x + 1 and x + 3x3 – 3x2 – 1.
2) Solve this problems Subtract 5x3 – 2x2 – 2 from x3 + 4x2 – 3x – 5
3) Find the product of 2x3 – 3x2 – 5 and 3x2 + 4x – 2 .
4) Solve the following system:x + y + z  = 4; x - 2y - z = 1; 2x - y - 2z = -1
5) Find the coefficients of a4, a3, a2 and a term in the product of 7a3 – 6a2 – 9a + 8 and 5a2 – 3a + 5 without doing actual multiplication.
6) Solve the equation by completing the square (2x - 3)2.
7) Solve the equation by completing the square x2 + 6x – 7 = 0.
8) What should be added with x2 + 12x to get a perfect square? What is that square?
9) Express (5 – 3i) 3 in the form a + ib.
10) Express (v3 + v2) (2 v3 -i) in the form of a + ib
11) Multiply (3AB + 2A)(A2 + 2AB2).
12) Multiply (X + Y)3
13) Find the statement is equal or not equal: 7(-4x - 3) - (x - 4) = -8(2x + 6) + 11
14) To find the equation of the line through the points (-8, -6) and (-5, 8), we first use the slope m.
15) Solve: 8x - 2y = 3
16) Solve the equation 2x4 -x4 -8x2 + 4x2 + 8x = 0x3 - 35, if one of its roots is 2 + v3 i
17) Solve the quadratic equation x2  + 7 = -x2
18) Solve the equation x4 - 4x2 + 8x = 0x3 - 35, if one of its roots is 2 + v3 i

Sample of Basic Algebra Test Answers:

1) 4x4 + 3x3 – 4x2 +3x + 0
2) –4x3 + 6x2 – x – 3.
3) 6x5 – 3x4 – 16x3 – 9x2 – 20x + 10.
4) The answer is (2, -1, 3).
5) So the coefficient of a term in X × Y is– 69; So the coefficient of a2 in X × Y is 37; So the coefficient of a3 in X × Y is 8; So the coefficient of a4 in the product of X × Y is –51.
6) 4x² - 12x + 9
7) The solution set = {1, –7}
8) 36.
9) – 10 – 198i.
10) (-6 + v2) +v3 (1+ 2 v2) i
11) 3A3B + 6A2B3 + 2A3 + 4A2B2
12) X3 + 3X2Y + 3XY2 + Y3
13) Not Equal.
14) Slope m =3/14
15) The x intercept is at the point (3/8 , 0).
16) Thus the roots are 2 ± iv 3 and - 2 ± i
17) (- 1 +v 3 i)/2 and (- 1 -v 3i)/2 are conjugate to each other.
18) Thus the roots are 2 ± iv 3 and - 2 ± i

Example problems for search answer to the algebra

Search algebra example problem 1:

Simplify the given [removed]13x + 23) + 50x = 10 - 43x

Solution:

Given expression is (13x + 23) + 50x = 10 - 43x

Expand the above expression, we get

13x + 23 + 50x = 10 - 43x

63x + 23 = 10 - 43x

Subtract (10 - 43x) on both the side of the equation, we get

106x + 13 = 0

Subtract 13 on both the sides, we get

106x = - 13

Divide the above equation by 106, we get

x = `(- 13 / 106)`

Answer:

The final answer is x = `(- 13 / 106)`

Search algebra example problem 2:

Find the x intercept of the given polynomial equation f (x) = 2x2 - 72

Solution:

The given polynomial equation is f (x) = 2x2 - 72

Plug f (x) = 0, for finding x intercept

0 = 2x2 - 72

Rearrange the above equation, we get

2x2 - 72 = 0

Add 72 on both the sides of the equation, we get

2x2 = 72

Divide the above equation by 2 on both the sides, we get

x2 = 36

Take square root on both the sides, we get

x = ± 6

x intercepts are ± 6

Answer:

The final answer is x = ± 6

Search algebra example problem 3:

Find the slope the line which passes through the (2, 8) and (0, 16).

Solution:

Given points are (2, 8) and (0, 16)

Here, x1 = 2, y1 = 8, x2 = 0 and y2 = 16

Slope formula:

Slope (m) = `((y_2 - y_1) / (x_2 - x_1))`

Substitute the given values in the above fomula, we get

Slope (m) = `((16 - 8) / (0 - 2))`

=` ((8 / - 2))`

= - 4

Slope of the line is m = - 4

Answer:

The final answer is m = - 4

Practice problems for search answer to the algebra

Search algebra practice problem 1:

Find the slope of the given straight line equation y = 5.3x - 17

Answer:

The final answer is slope (m) = 5.3

Search algebra practice problem 2:

Find the factors of the given quadratic equation x2 - 17x + 60 = 0

Answer:

The factors are (x - 12) and(x - 5)

Search algebra practice problem 3:

Simplify the expression 5x + 28 = 108

Answer:

The final answer is 16

Article Source: http://www.articlesbase.com/k-12-education-articles/sample-of-basic-algebra-test-6619407.html

About the Author

Between, if you have problem on these topics Examples of Consecutive Interior Angles, please browse expert math related websites for more help on Math Tutoring and different math topic.

Pre algebra review tests

Author: Matthew David

Pre algebra review tests

Introduction to pre algebra review tests:-

In this article we are learning about the pre algebra review tests the concept. Algebra is cluster of mathematics and it process on the pre algebra review tests. Pre algebra review tests cover the four basic operations such as addition, subtraction, multiplication and division. The most important expression of pre algebra review tests is variable, constant coefficient, exponent, word and expression. Pre algebra review tests beside numeral we use symbol and alphabet in place of unknown number to make a statement. Hence, pre algebra review tests related problem shown below.

Pre-algebra is division of mathematics is that replacement letters for numbers. An algebraic equation is stand for the scale, what is finished on the one side of a scale with a number is also completed to the other side of the scale. This type of mathematics is called algebra. In this article we shall discuss about how to do pre-algebra problems with some examples.

Sample problem for how to do pre algebra:

Problem 1:

Find the value of given fraction numbers `2/3 ` + `1/3`

Solution:

In the proper fraction a denominator values are same. So we are directly added or subtract the numerator values.

Step 1: In here the denominator values are same.

Step 2: Add the numerator values and place over the same denominator values.

`2/3 ` + `1/3`= `(2 + 1)/3`

= `3 / 3`

Step 3: Now we are simplify the fraction values

= 1

Problem 2:

Solve the given values using simple arithmetic operations 9 + (7 * 2)

Solution:

We are going to find the value of given numerical values.

In the first step we are going to multiply the values 7 and 2, we get

7 x 2 = 14

In the next step add the value 14 and 9, we get

9 + 14 = 23

The sum value of the given numerical value is 23.

Pre-algebra Problem 3:

Evaluate the given problem and find the sum value 6 - `(8 / 2^2)`

Solution:

We are going to find the value of given numbers.

In the first step we are going to find the value of 8 and 22, we get              

`8 / 2^2 ` =` 8 / 4`

= 2

In the next step we are subtract the two terms 6 and 2 we get

6 – 2 = 4

The sum value of the given terms is 4.

Problem 4:

Solve the given equation X – 5 = 8.

Solution:

We are going to find the x value of the given equation. In the first step move -5 into the right side of the equation, we get

X = 8 + 5

X = 13

We get x value as 13.

Pre algebra review tests questions:-

1. Write b. b. b. b. b. a. a. a in exponential form.

2. Evaluate `x^4.y^2` when x = 2 and y = 5

3. What is the square of 13?

4. Find the quotient of 3270 and 32.

5. a. Find 0/16 b. Find 16/16 c. Find 16/0 d. Find 16/1

6. Simplify: 8+`6^2` +8÷2

7. Simplify: 20 + 4(5)

8. Simplify: 43+6·12-6÷2

9. Find the opposite of –6.

10. Find the opposite of 12.

11. Write the expression –4-(-3) in words.

12. Simplify: -(9)

13. Add.-31+75+ (-69)

14. What is 22 added to –19?

15. Evaluate the expression – a + b-c, when a = -6, b =4, and c = -3.

16. Use the Inverse Property of Addition to complete the statement_____+12=0

17. What is –21 decreased by –13?

18. Simplify. 13+ (-9)-18-(-5)-3+14

19. Evaluate yx--, when x = -12 and y = -23.

20. Is –11 a solution to 5-(-x) =16?

21. Find the temperature after a rise of 22° F from -31°F.

22. Solve -7+x=-5

23. Solve -4n=56.

24. The difference between a number and seven is twenty-eight. Find the number.

pre algebra review tests answer keys:-

1. `a^3b^5`

2. 400

3. 169

4. 102 R 6

5. a. 0 b. 1 c. undefined d. 16

6. 48

7. 40

8. 13 9. 54

9. 6

10. -12

11. negative four minus negative three

12. 3

13. –25

14. 3

15. 13

16. –12

17. –8

18. 2

19 35

20. NO

21. -9° F

22. x = 2

23. n = -14

24. x = 35.

Article Source: http://www.articlesbase.com/k-12-education-articles/pre-algebra-review-tests-6617765.html

About the Author

Between, if you have problem on these topics Solving Quadratic Equations by Completing the Square, please browse expert math related websites for more help on Find the Median and different math topic.

5 Significant Strategies to Improve Your Children's Math Score

5 Significant Strategies to Improve Your Children's Math Score
By B. Jacob

Math is one of the highest scoring subjects and by gaining a good score in math; students can have an overall commendable grade in exams. The only one thing needed to achieve good grades, is constant practice. Research suggests that math is different from other subjects and it improves student's reasoning skills. Parents are always conscious about their children and they do their level best in improving their scores in exams. Parents are also known as the first tutors so in that respect, they play a vital role in their children's lives. They can boost their children's confidence and support them to achieve their learning goals.

Parents are the ideal mentors for their children. They can bring about some positive changes in their children's lives. Five easy and useful steps are discussed below that can make your children good scorers in math.

Help children in managing time: Time management skill is highly required for students to score well in exams. If students can properly divide their time for each question, then they can easily solve the entire test paper on time. Parents should teach them the importance of time management. This skill helps children in organizing their career, as well.

Hire a good math tutor: Parents should choose an experienced tutor for their children. An experienced subject expert can only assist his/her student in a better way. Neither parents can be available all the time nor do they help their children in all subjects. Therefore, taking learning help from proficient professionals is the best way to get knowledge on each topic. They can choose online tutors, as well. While choosing a tutor, parents should check some information such as the qualification and experience and the flexibility in terms of time.

Provide useful math worksheets: Several free math worksheets are available online. Parents can download and provide these to their children as working on these worksheets surely improves their skills. Parents can also encourage them to practice these worksheets repeatedly. It is one of the convenient ways to brush up your knowledge on a particular topic.

Motivate children to improve their weak areas: Some times, children cannot find out their weak areas and repeat their mistakes again and again. In that respect, parents should play a significant role to make their children understand faults. They can also show ways to improve their errors.

Provide moral support: Children generally depend on their parents most. They rely on their parents in many aspects. They need their parents the most especially when they face some unmanageable difficulties or problems. In that case, parent's moral support works as healing mantras to them. Many failed students can again do better results by having moral support from their parents.

To improve your maths you have to work hard on the subject there are different ways to overcome from the problems like you can get help through free online math tutor and math problem solver and more practice with the problems.

Article Source: http://EzineArticles.com/?expert=B._Jacob
http://EzineArticles.com/?5-Significant-Strategies-to-Improve-Your-Childrens-Math-Score&id=7672994

What is a functions operations algebra 2

Author: Matthew David

What is a functions operations algebra 2

Introduction of what is a function algebra 2:

Function algebra 2 is a  branch of mathematics to find unknown variable from the expression with the help of known values. The algebraic expression deals with variables, the variable are represents by alphabetic letters. In functions algebra 2 numbers are constant, algebraic expression may include  real number, complex number, and polynomials. Functions in  algebra 2 may include in the function of p(y), q(y),… to find the x value of the algebra functions.

For example:

Function algebra 2 may be described in this form p(y) = 2y2+3y + 4. In this function we need to find the function variable y as 2.

Functions operation algebra 2 finding unknown variable from the given expression with the help of known values. The algebraic expression contains variables are represented alphabetic letters.  The functions operations algebra 2 looks f(x), q(x),… to find the x value of the algebra functions.There are several operation of function as show in below

Functions operations algebra 2:

    (f + g)(y) = f (y)+ g (y)
    (f – g)(x) = f (y)–g (y)
    (f .g)(x) = f (y).g (y)
    `(f/g)` (x)=`(f(y))/(g(y)).`
    
Addition and subtraction problems in the functions operations algebra 2:

Problem (i): Adding two functions operations f(x) = x+2 and g(x) = x-3 find (f+g)(x).

Solution: Adding two function using the functions operations algebra 2.

Given f(x) = x+2 and g(x) = x-3 find (f+g)(x).

Using the functions operations of  (f + g)(x) = f (x)+g (x).

(f+g)(x) = (x+2)+(x-3).

(f+g)(x)= x+x+2-3 in this step adding both functions.

(f+g)(x) = 2x-1.

Problem (ii): subtracting two functions operations f(x) = (x+5) and g(x) = (x-8) find (f-g)(x).

Solution: Subtracting two functions using the functions operations algebra 2.

Given f(x) = x+5 and g(x) = x-8 find (f-g) (x).

Using the functions operations of (f - g)(x) = f (x)-g (x).

(f-g)(x) = (x+5)-(x-8).

(f-g)(x)= x-x+5-8 in this step subtracting both functions.

(f-g)(x) = -3

Multiplying and division problems in the functions operations algebra 2:

Problem (i): multiplying two functions operations f(x) = x+5 and g(x) = x-8 find (f.g)(x).

Solution: multiplying two functions using the functions operations algebra 2.

Given f(x) = x+5 and g(x) = x-8 find (f.g) (x).

Using the functions operations of (f . g)(x) = f (x). g (x).

(f.g)(x) = (x+5) . (x-8).

(f.g)(x)= x2-8x+5x-40 = x2  - 3x -40 in this step multiplying both functions.

Problem (i): dividing two functions operations f(x) = 10x and g(x) = 2x find `(f/g)` (x).

Solution: multiplying two functions using the functions operations algebra 2.

Given f(x) = 10x and g(x) = 2x find `(f/g)` (x).

Using the functions operations of `(f/g)` (x) = `(f(x))/(g(x)).`

`(f/g)` (x) = `(10x)/(2x)` in this step x will be cancelled.

`(f/g)` (x)= 5 in this step dividing both functions

Example Problems for what is a function algebra 2

Simplify using the square function algebra 2.

Problem1; Using square functions. What is a function algebra 2 in. p(x) = x2 +6x +14 find the p(6).

Solution :

Find the function p(6). Here substitute the value 5 to the variable.

p(x) = x2 +6x +14 find the f(6).

The value of x is 6 is given

p(6) = 62 +6*6 +14

p(6) = 36 +36 +14 In this step 62 is 36 it is calculate and 6*6 is 36 be added

p(6) = 86.

The functions algebra 2 p(6) = x2 +6x +14 find the p(6) is 86.

Problem2; Using square  function algebra 2. z(x) = x2 +6x +25 what is a function algebra 2 in z(7).

Solution :

Find the function y(7). Here substitute the value 7 to the variable.

z(7) = x2 +6x +25 find the z(7).

The value of x is 3 is given

z(7) = 72 +6*7 +25

z(7) = 49 +42+25.

z(7) = 116.

z(7) = x2 +6x +25 find the y(7) is 116.

Functions algebra 2 problems using the cubic functions

Problems1: using the cubic function algebra 2: f(x) = x3 +2x2 + 2x + 4 What is a function algebra 2 in f(2).

Solution:

Find the function f(2). Here substitute the value 2 to the variable.

f(x) = x3 +2x2 + 2x + 4 find the f(2).

Here the value of x is given as 2

f(2) = 23 + 2*22 + 2*2 +4

f(2) = 8 +8+4 +4 In this step 23 is calculated  as 8 and 2 square is 4

f(2) = 24.

f(x) = x3 +2x2 + 2x + 4 find the f(2) = 24.

Problems 2: what is a function algebra 2 in cubic equations. f(x) = 2x3 +4x2 + 3x + 24 find the functions algebra 2 of f(4).

Solution:

Find the function f(4). Here substitute the value 4 to the variable.

f(x) = 2x3 +4x2 + 3x + 24 find the f(4).

Here the value of x is given as 3

f(4) = 2*43 + 4*42 + 3*4 +24

f(4) = 128 +64+12 +24

f(4) =  228

f(x) = 2x3 +4x2 + 3x + 24 find the f(4) = 228.   

Article Source: http://www.articlesbase.com/k-12-education-articles/what-is-a-functions-operations-algebra-2-6619384.html

About the Author

Between, if you have problem on these topics Consecutive Interior Angle Theorem, please browse expert math related websites for more help on Math Questions and different math topic.

Getting Better Test Scores On Your Math Test

Getting Better Test Scores On Your Math Test
By Andrew Almeida

Do you or your children get bad math test scores? This article will teach you three techniques on how to get better math test scores. The three techniques we will explore focus on the problem, testing the problem, and pacing yourself to finish. Let's just face it math tests are not a, b, c, and d bubble answer questions. Math tests are usually a problem and then you have to "write out your work". So this article will not tell you to pick the best answer or choose the longest answer when in doubt.

Focusing on the problem is a major technique that will get you through the problem and also help pace yourself throughout the test. The word "focus" says it all. Tune out the noises around you, the thoughts of our boyfriend or girlfriend, the "being cool by not knowing math" posture, and the anxiety of taking the test. I used to have anxiety during my physics test, but after learning the art of "focus" the anxiety will go away. The key to focusing on the problem is read the problem a few times. Think of your solution and how you are going to get there and then carefully write out your work. If you need scratch paper 99% of teachers encourage using scratch paper for thoughts. If you absolutely cannot get to the answer write down as much as you know to get the most credit possible for that question. Teachers do not just grade on the answer. They also give points for the work your write down.

Testing the problem comes after focusing on the problem. In order to test the problem you must have focused on the problem and written down your work and have a rough answer. The answer might be "certain" in your eyes, but one tiny number or issue can make that problem wrong. Yes, teachers give points for work, but they grade the heaviest on the right answer. Therefore testing the answer is a key technique in getting a better test score. So how do you test your answer? Well in mathematics both sides of the equal sign must be equal. So if A+B = C, then you know that C = A+B. Or A = C-B and B = C-A. They are equal because, well, they have to be. The equal sign is powerful and makes that true. Therefore to test your work plug in the numbers that you got and see if both sides of the equal sign is equal to each other. For example: If the problem was 42/x + 7 = 28 and you did the problem to get X = 2 then in order for you to test it out you would plug in 2 and get 42/2 + 7 = 28 and if you work through it you will get that 28 = 28. Done.

The test is usually timed for the entire class period whether it is fifty minutes or an hour you must pace yourself. The teacher isn't evil and will not make a test they feel cannot be finished within the time limit. They usually do the test themselves when they write it to see whether or not the test is good for time. So pacing yourself to finish is a key ingredient to a better test score. If you do not know the answer to a question you would write down what you know whether it is the formula, a strategy, or the start of the problem and then move on. You should get a few points for your knowledge. After you get through all of the problems on the test, you would have to go back and tackle the harder questions that stump you before. Sometimes, by moving on and coming back you will exercise your brain enough to recall the part that made you skip it to begin with. Pacing yourself to finish the test is extremely important. Pacing comes with the experience of taking tests. To practice pacing have your parent or use a text book and write out a test. Then take the test to practice pacing.

In conclusion, you will get a better math score (and pass) by following the three techniques in this article. Focus on the problem, test the problem, and pace yourself throughout the test and you will surely get a better score! Not everyone is perfect at math so do not let that be a barrier or burden while you take the test. You may get some questions wrong, but remember the three techniques and you will do better.

Ask a math question and learn more about math tests at http://www.helpinmathplease.com.

Article Source: http://EzineArticles.com/?expert=Andrew_Almeida
http://EzineArticles.com/?Getting-Better-Test-Scores-On-Your-Math-Test&id=7688572

Math made easy algebra rules

Author: Matthew David

Math made easy algebra rules

Introduction to math made easy algebra rules:

Algebra is defined as one of the basis of mathematics.  Mainly algebra is used to study about the rules and the properties. There are many other operations are related to the algebra. In the pure mathematics, algebra is defined be one of the main branches. Algebra can uses the various symbols, letters and numbers.

Algebra is a branch of mathematics. Algebra plays an important role in our day to day life. To teach the algebra in the easy way, we have to educate the four basic operations in algebra such as addition, subtraction, multiplication and division. The most important terms of algebra, variables, constant, coefficients, exponents, terms and expressions are used to teach algebra in the easy way. When we want to teach algebra in the easy way, we are using the symbols and alphabets instead of unknown values to make a statement. Hence, the easy way to teach algebra regards the leads of Arithmetic.

Explanation for the math made easy algebra rules

There are many rules are followed in the algebra which made easy to study. They are given below the following,

    Commutative property used for the addition operation.

Rule: p + q = q + p

    Commutative property used for the multiplication operation.

Rule: p * q = q * p

    Associative property used for the addition operation.

Rule: (p + q) + r = p + (q + r)

    Associative property used for the multiplication operation.

Rule: (p * q) * r = p * (q * r)

    Distributive property used for addition operation over the multiplication operation.

Rule: 1.p * (q + r) = p * q + p * r
         2. (p + q) * r = p * r + q * r

    The reciprocal for an non-zero number b is given by `1/p`

Rule: p*( `1/p` ) = 1

    The additive inverse process of the number b is given by –b.

Rule: p + (- p) = 0

    The additive identity used is 0.

Rule: p + 0 = 0 + p = p

    The multiplicative identity used is 1.

Rule: p * 1 = 1 * p = p

Example problem for math made easy algebra rules

Commutative property used for the addition operation:

Problem 1: Use the given value in the commutative rule, p = 5, q = 6

Solution:

Rule: p + q = q + p

By substituting the values , we get,

5 + 6 = 6 + 5

11 = 11

Commutative property used for the multiplication operation:

Problem 2: Use the given value in the commutative multiplication rule, p = 5, q = 6

Solution:

Rule: p * q = q * p

By substituting the values , we get,

5 * 6 = 6 * 5

30 = 30

Associative property used for the addition operation:

Problem 3: Use the given value in the associative rule, p = 5, q = 6, r = 2

Solution:

Rule: (p + q) + r = p + (q + r)

By substituting the values , we get,

( 5 + 6 ) + 2 = 6 + (  5 + 2 )

( 11 ) + 2 = 6  + ( 7 )

13 = 13

Example 1:

Solve the equation for x, 3(5x) = 45.

Solution:

3(5x) = 45 (3 is multiplied within the parenthesis)

3 * 5x = 45

15x = 45 (divide both sides by 15)

`(15x) / 15 = 45 / 15`

x = 3

Example 2:

Solve the equation for x, 2(2x-5) = 50.

Solution:

2(2x-5) = 50 (2 will be multiplied within the parenthesis)

(2 * 2x) – (2 * 5) = 50

4x – 10 = 50 (add both sides by 10)

4x  - 10 + 10 = 50 + 10

4x = 60 (divide both side by 4)

`(4x)/4 = 60/4`

x = 15

Example 3:

Solve the equation for x, `(5x-5) / 3` = 10.

Solution:

`(5x-5) / 3` = 10 (multiply both sides by 3)

`(5x-5) / 3`  * 3 = 10 *3

5x – 5 = 30 (add both sides by -5)

5x – 5 + 5 = 30 + 5

5x = 35 (divide both sides by 5)

`(5x) / 5= 35 / 5`

x = 7

Example 4:

Solve the equation 5x + 5 = x + 55 for x.

Solution:

5x + 5 = x + 55 (add both sides by -5)

5x + 5 – 5 = x + 55 - 5

5x = x + 50 (add both sides by -x)

5x – x = x – x + 50

4x = 50 (divide both sides by 4)

`(4x) / 4 = 50 / 4`

x = 12.5

Example 5:

Solve the equation 2x – 5 = 45 for x.

Solution:

2x – 5 = 45 (add both sides by 5)

2x – 5 + 5 = 45 + 5.

2x = 50 (divide both sides by 2)

`(2x) / 2 = 50 / 2`

x = 25

Practice problem for math made easy algebra rules

Problem 1:

Solve the equation for x, 15x + 5 = 65.

The answer is x = 4

Problem 2:

Solve the equation for x, 6x – 1 = 35

The answer is x = 6

Problem 3:

Solve the equation for x, 6x + 4 = 28

The answer is x = 4

Problem 4:

Solve the equation for x, 3x - 5 = 35 - x

The answer is x = 10

Problem 5:

Solve the equation for x, 4x + 2 = 34 + 2x

The answer is x = 16

Problem 6: Use the given value in the commutative rule for addition, p = 10, q =20

Answer: 30

Problem 7: Use the given value in the associative rule for addition, p = 2, q = 4, r =6

Answer: 12

Article Source: http://www.articlesbase.com/k-12-education-articles/math-made-easy-algebra-rules-6619362.html

About the Author

Between, if you have problem on these topics Consecutive Exterior Angles Theorem, please browse expert math related websites for more help on math problem solver and different math topic.

Number Sense Tutorial

Author: nayaknandan85

Introduction to number sense tutorial:

In mathematics, number system is called as system of numeration. Number systems are used to express the quantities for counting, defining order, comparing the quantities, calculating numbers and denoting values. Number system includes natural numbers, integers, rational numbers, algebraic numbers, real numbers, complex numbers, p-adic numbers, surreal numbers and hyper real numbers.

Number sense is explained with examples and practice problems very interactively by tutorial. So students are getting number sense help by tutorial for their studies.

Examples to number sense tutorial:

Example 1:

Add the following decimal numbers 65.45 + 6.892

Solution:

Addition operation for decimal numbers is just like the integers addition. In this problem

65. 45 has two decimal place but 6.892 has three decimal place. Hence, we have to add 0 with the number 65.45, so we get 65.450

That is, 65.45+6.892 = 65.450+6.892

11 1
65.450
+ 6.892
72.342

Example 2:

Find the square root of the following numbers `sqrt(289)` .

Solution:

`sqrt(189) ` = `sqrt(17 xx 17)` = 17

Example 3:

Write the standard for the following number 69.089 `xx` `10^3`

Solution:

69.089 `xx` `10^3` which can be written as

69.089 `xx` 10 `xx` 10 `xx` 10

69.089 `xx` 1000 now we have to shift the decimal point to three decimal point. So that we will get

69089

Example 4:

Add the following mixed numbers `8 1/3` and `8 1/4` .

Solution:

We have to convert the following mixed numbers in to improper fraction. For this, denominators are multiplied with the whole number and then add the result of the product with numerator. So that, we will get the improper fraction.

`8 1/3` => `((8 xx 3) + 1)/3` => `(24 + 1)/3` => `25/3`

`8 1/4` => `((8 xx 4) + 1)` => `(32 + 1)/4` = `33/4`

Now we can add both improper fraction

`25/3` + `33/4` here, denominators are not same. So that, we have to find LCM. The LCM is 12

The denominator 3 from the fraction `25/3` is 4 times in the LCM. So we have to multiply the numerator 25 by 4. So we get `100/12`

The denominator 4 from the fraction `33/4` is 3 times in the LCM. So we have to multiply the numerator 33 by 3. So we get `99/12`

`(100 + 99)/12`

`199/12`

Practice Problems to number sense tutorial:

Problem 1:

Add the following decimal numbers 6.45 + 6.82

The answer is 13.27

Problem 2:

Find the square root of the following numbers `sqrt(324)` .

The answer is 18

Problem 3:

Write the standard for the following number 675.89 `xx` ` 10^3`

The answer is 675890

Problem 4:

Add the following mixed numbers `1 5/3` and `2 6/4` .

The answer is `22/12`

In mathematics, number system is called as system of numeration. Number systems are used to express the quantities for counting, defining order, comparing the quantities, calculating numbers and denoting values. Number system includes natural numbers, integers, rational numbers, algebraic numbers, real numbers, complex numbers, p-adic numbers, surreal numbers and hyper real numbers.

Article Source: http://www.articlesbase.com/k-12-education-articles/number-sense-tutorial-6617763.html

About the Author

Comprehend more on about consecutive integer and its Circumstances. Between, if you have problem on these topics Linear Inequalities Please share your views here by commenting.

Some Simple Steps to Improve Math Grades

Some Simple Steps to Improve Math Grades
By Sandy D'Souza

Math is a basic subject and hence, it is included in the curriculum from the kindergarten level. However, doing math is not at all a good experience for all students. The subject needs more concentration and step-by-step understanding. Students cannot follow the same methodology for math preparation as they generally do for other subjects including geography, chemistry, physics and others. Math needs more practice and this is one of the subjects in which students can score well and improve their overall grades in exams. This subject has broad real life applications from purchasing groceries to maintaining bank transactions. We use math everywhere. We start learning math from our childhood days, for example counting flowers and birds with our parents. Moreover, some students face difficulties while solving math and to overcome these learning problems, some steps are discussed below.

1. Regular attendance classes at school are a must for students. In this way, students can be familiar with mathematical problems. Additionally, the habit of solving math problems on a regular basis can be inculcated in students. Students can understand their own weak areas, as well.

2. Re-practice of class work at home is also required. Class timings at school are limited so both students and tutors do not put in enough time on each topic. Therefore, students should practice the class work again at home and solve their problems. They can work on different examples and later, discuss these with their tutors.

3. Do homework regularly and practice each concept on a regular basis. Some students face difficulties and without solving these, they move on to other topics. Hence, they cannot make out any topic properly and end up with a bad experience. It is thus advisable to understand math concepts step-by-step and solve problems repeatedly.

4. Start test preparation much before exams to get a better result. Students should have adequate time in their hand to revise the entire syllabus thoroughly. Math is that kind of subject which cannot be grasped in a hurry. Students should revise each math topic at their own pace. They can download several math worksheets online and practice these to get proficiency on each topic.

5. Clear your doubts thoroughly and memorize formulas for their right implementation. Understanding math formulas are not enough to score well in exams. Students should know their right implementation and hence, they can achieve their learning goal.

6. Take learning help from online tutors at your convenient time. Online tutoring is a proven method to get requisite learning help whenever required. This innovative tutoring process doesn't have any time and geographical restriction. Students from any part of the world can access this learning session especially for math by using their computer and internet connection. Most importantly, the beneficial tools like the white board and attached chat box which are used in this process make the entire session interactive and similar to live sessions. Hence, it enhances student's confidence and meets their overall educational demands in the best possible manner.

Students can get help on steps to improve their grades in Maths, and they can also work on different grades like 7th grade math and with online Math help students can work on different math related topics.

Article Source: http://EzineArticles.com/?expert=Sandy_D'Souza
http://EzineArticles.com/?Some-Simple-Steps-to-Improve-Math-Grades&id=7673063

Algebra 1 connections answers

Author: Matthew David

Algebra 1 connections answers

Introduction to algebra:

Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics. In this article we shall discuss for need help with algebra 1 math.   (Source: Wikipedia)

Sample problem for need help with algebra 1 math

Need help with algebra 1 math problem 1:

Solve the given linear equation

8x+ 8y = 24,

8y +8 z = –40,

8z + 8x = 16.

Solution:

The given equations can be written as

8x + 8y = 24 ----------- (1)

8y + 8z = –40 -------- (2)

8z + 8x =   16 ----------- (3)

Adding all the equations,

8x + 8y + 8z = 24 + (–40) + 16

Or          8(x + y + z) = 0

In the above equation is divided by 2 we get

8x +8 y +8 z = 0 ----------- (4)

Substituting 8y + 8z = 16 in equation (4) we get

8x + (–40) = 0

8x = 40

X = 5

Substituting 4x + 4y = 12 in equation (4) we get

4y + 20 = 12

4y = –8

Y = -2

Substituting x = 5 in equation (3) we get

8z + 8x = 16

8z + 8*5 = 16

8z = 16–40

8z = -24

z = –3

The solution is x = 5, y = –2, z = –3.

Need help with algebra 1 math problem 2:

Solve the given linear equation

10x+ 10y = 32,

10 y +10 z = –50,

10z + 10x = 20.

Solution:

The given equations can be written as

10x + 10y = 32 ----------- (1)

10y + 10z = –50 -------- (3)

10z + 10x = 20 ----------- (3)

Adding all the equations,

20x + 20y + 20z = 32 + (–50) + 20

Or          20(x + y + z) = 0

In the above equation is divided by 2 we get

10x + 10y + 10z = 0 ----------- (4)

Substituting 10x + 10y = -50 in equation (4) we get

10x - 50= 0

10x = 50

X = 5

Substituting 10z + 10x = 20 in equation (4) we get

10y + 20= 0

10y = –20

Y = -2

Substituting x = 5 in equation (3) we get

10z + 10*5 = 20

10z = 20–50

10z = -30

z = –3

The solution is x = 5, y = –3, z = –3.

Algebra 1 connections example problem 1:

Solve the linear function y = 2 - x and x - y = 10

Solution:

Given equations are,

y = 2 - x --------- (equation 1)

x - y = 10 -------- (equation 2)

Substitute the equation 1 into equation 2, we get

x - (2 - x) = 10

Rearrange the above equation, we get

x - 2 + x = 10

2x - 2 = 10

Add 2 on both the side of the equation, we get

2x = 12

Subtract the above equation by 2, we get

x = 6

Substitute x = 6 in equation 1, we get

y = 2 - 6

y = - 4

Answer:

The final answer is x = 6, y = - 4.

Algebra 1 connections example problem 2:

Simplify the given [removed]4x + 43) + 12x = 52 - 2x

Solution:

Given expression is (4x + 43) + 12x = 52 - 2x

Expand the above expression, we get

4x + 43 + 12x = 52 - 2x

16x + 43 = 52 - 2x

Subtract (52 - 2x) on both the side of the equation, we get

18x - 9 = 0

Add 9 on both the sides, we get

18x = 9

Divide the above equation by 18, we get

x = `(9 / 18)`

Answer:

The final answer is x = `(1 / 2)`

Algebra 1 connections example problem 3:

Find the x intercept of the given polynomial equation f (x) = x2 - 225

Solution:

The given polynomial equation is f (x) = x2 - 225

Plug f (x) = 0, for finding x intercept

0 = x2 - 225

Rearrange the above equation, we get

x2 - 225 = 0

Add 225 on both the sides of the equation, we get

x2 = 225

Take square root on both the sides, we get

x = ± 15

Answer:

The final answer is x = ± 15

Practice problems for algebra 1 connections answers

Algebra 1 connections practice problem 1:

Solve the linear function y - 2 = x and 4x + y = 22

Answer:

The final answer is x = 4, y = 6

Algebra 1 connections practice problem 2:

Factorize the equation x2 + 22x + 40 = 0

Answer:

The final answer is x = - 20 and x = - 2

Article Source: http://www.articlesbase.com/k-12-education-articles/algebra-1-connections-answers-6619317.html

About the Author

Between, if you have problem on these topics Acute Angles, please browse expert math related websites for more help on Geometry Tutor and different math topic.

Identify the Correct Statement

Author: Omkar

Introduction to identify the correct statement

In this lesson we will see how to handle multiple choice questions effectively. These questions differ from other detailed problem solving as the student is provided with choices of various answers and the student is required to identify the correct answer. Normally four to five alternatives are provided, out of which usually one is correct but occasionally some multiple choice questions will have more than one correct answer. Normally, examinations with only multiple choice questions come with time constraints and in some cases a penalty is imposed for wrong answers to avoid wild guessing. It is therefore important that this section is attempted quickly and accurately.

As said above, the success in attempting these questions will depend on the ability to identify the correct answer quickly. It might not be required to solve the problem from beginning to end. The student might have enough hints to identify the wrong choice. Some of the problems will require solving up to a stage and then eliminating the wrong answers. In some cases it will be good to try working from the alternatives given into the questions and eliminate the wrong ones.

Approaches to identify the correct statement

Main approaches

Identify and eliminate wrong alternatives
Find the range of values for the possible answer or the sign of the number etc and eliminate the alternatives that are outside the range
Try plugging the alternatives in the conditions mentioned in the problem statement and see if all the conditions are met. This will help in eliminating the wrong alternatives quickly
Let us analyze the various approaches to identify the correct statement without actually spending time to solve the problem and arrive at the final answer

Ex 1: What is the value of `sqrt(52.4176)`

A) 6.94

B) 3,88

C) 7.86

D) 7.92

Sol: It will be extremely time consuming to actually find the square root of the number 52.4176 without a calculating device. Moreover, the chances of making a mistake in calculations are also high.

Step 1: Let us first take the integer part and then identify the perfect squares near by.

The integer part of 52.4176 is 52 and the perfect squares near by are 49 and 64.

`sqrt(49)` = 7 and `sqrt(64)` = 8.

So `sqrt(52.4176)` lies between 7 and 8.

Step 2: This will eliminate the first two choices. We are now left with choices 7.86 and 7.92. One of these numbers if multiplied by itself should get 52.4176.

Note, that 52.4176 ends with 6.

Step 3: So the if we try multiplying 7.92 by 7.92, the end digit will have 4 ( as 2 x 2 = 4) and not 6. So 7.92 is not the right answer. The only alternative left is 7.86 and when multiplied by itself will get a number ending with 6. This is the correct choice

Ans: (C) 7.92

The above approach will considerably save time and effort to identify the answer. Note, we identified the answer, we did not work out the answer. In multiple choice questions this approach is very important

Another approach is to work from the alternatives that satisfy the conditions in the question. This approach will be faster in many cases

Let us now try another example

Ex 2: Given b = 2a, Find the values of a,b and c if, `(21a)/(c) = (b+c+1)/(a)= (2c+5a)/(b)`

A) a= 3,b= 6,c= 7

B) a= 2,b= 4,c= 7

C) a=4,b=8, c=2

D) a=1,b=7,c=6

Sol: It will be too time consuming to solve the equations and to arrive at the values for a, b and c. It will be easier if we plug in each alternative into the conditions of the question and eliminate the ones that does not satisfy.

Step 1: First condition is b = 2a, we can easily see that alternative (D) does not satisfy this condition and can be eliminated. We are now left with (A), (B) and (C) only.

Step 2: Let us try the alternative A: `(21a)/(c) = 21*3/7` = 9 and `(b+c+1)/(a) = (6 +7+1)/(3)` = 4.67. These are not equal and hence alternate (A) is not correct

Step 3: Let us try the alternative B: `(21a)/(c) = 21 * 2/7` = 6 and `(b+c+1)/(a) = (4+7+1)/(2)` = 6 and

Step 4: `(2c+5a)/(b)= (2*7 + 5*2)/(4) = 24/4` = 6.These are all equal to 6 and hence alternate (B) is correct

Step 5: To complete let us try alternate C as well

`(21a)/(c) = 21 * 4/2` = 42 and `(b+c+1)/(a) = (8+2+1)/(4)` = 2.75. These are not equal and hence alternate (C) is not correct

Ans: (B) a= 2,b= 4,c= 7

We will look at one more approach to identify the correct statement

Let us consider another example

Ex 3 : What are the roots of the quadratic equation, 3.1x2 –2.1x – 6.9 = 0

A) 1.47, 3.30

B) 2.1, -3.6

C) –3.2, -1.8

D) 1.87, -1.19

Sol: If we solve the problem using the quadratic formula, it will take a long time as it will involve find the square root of fractional numbers etc. To identify the correct statement among the above four, this is not required either. If we use the formula connecting the roots of the quadratic equation, we can eliminate the alternatives easily

Step 1: We know Sum of roots is `-b/a`

Product of roots is `c/a`

Step 2: If we apply this for the above equation we get

Sum of root of the equation 3.1 x2–2.1 x – 6.9 = 0 is `2.1/3.1` an dpreoduct of the root is –6.9/3.1

Step 3: The product of roots is negative. This means that we will have one root with positive sign and another with negative sign. This will eliminate alternatives (A) and (C). We now need to pick from alternatives (B) and (D)

Step 4: Sum of the roots is positive, this means that the absolute value of the positive root is higher than the negative root. This will eliminate alternative (B)

The only alternative left is (D)

Ans: (D) 1.87, -1.19

Thus we could identify the correct statement without doing any calculation

Exercise on correcting statements

Pro 1: What is the value of Sin 470?

A) 0.31

B) 0.94

C) 0.731

D) 0.26

Hint: Value of Sin 0 increases from 0 to 1 as theta moves from 0 to 90

Ans: C

Pro 2: Which of the following triplets that best forms the sides of a right angled triangle?

A) 13.1,16.7, 28.51

B) 15.2,16.7, 30.4

C) 17.8,19.6,35.7

D) 24.3,15.2,28.66

Hint: Use the principle that sum of any two sides of a triangle is greater than the third side. This will help in eliminating the alternatives

Ans: D

Pro 3 : what is the value of 6.812-3.922?

A) 28.635

B) 31.097

C) 15.637

D) 38.927

Ans: B

Article Source: http://www.articlesbase.com/k-12-education-articles/identify-the-correct-statement-6617590.html

About the Author

Comprehend more on about normal distribution problems and its Circumstances. Between, if you have problem on these topics poisson distribution formula Please share your views here by commenting.

Some Useful Ways to Get Good Scores In Math Exams

Some Useful Ways to Get Good Scores In Math Exams
By B. Jacob

Math is different when compared to other subjects like history and geography. Most students think that they can prepare for the math exam in the same way as they usually prepare for History and English exams. Using the same style of preparation leads students to disappointment and they become less interested in math. Additionally, unexpected results in math may make them unhappy. Memorizing formulas are not enough for math; students should know their proper implementation to get a good score in this subject. Experts suggest that practice is something that only enhance math problem solving skills and also enable students to understand math in step-by-step manner.

Several ways are there to help students improve their math score. These tips or ways are useful for students who badly need to improve their grades in math exams.

1. Regularly attending classes at school are good for students. They can acquire knowledge and also work on problem areas. Students should jot down their learning problems and the examples which are taught in class. Later, they can work on them to overcome their difficulties.


2. Apart from regular classes at school, students can take learning help from online tutoring. With this service, they can take personalized sessions at their preferred time from home. It not only saves their time but also imparts adequate knowledge in a comprehensible manner. Moreover, students can revise any topic in a short span of time. Besides this, they can get beneficial tips from subject experts before their exams.


3. Solve one math sum by using different methods. Students can solve one problem in different ways. They can choose the way in which they feel comfortable. It enhances their proficiency level, as well.


4. Follow texts as well as examples to learn one topic thoroughly. Study material contains both text and examples and these help students to understand the basic concepts behind each formula.


5. Sometimes, group study can be helpful for students to grasp the subject in an easy way. Students can discuss their problems and share the solutions of any tough mathematical problem with others.


6. Learn math in a step-by-step way. Some topics are quite inter-linked and students may face the same math problem which they had experienced earlier. Sometimes, without comprehending a topic properly, students cannot understand the next one. So it is advised to learn math in a sequential manner.


7. After completion of one topic, students should check their proficiency by giving a test. They can judge their expertise and also check their time management skill.


8. Most importantly, students should start exam preparation far before the final exam. It gives them sufficient time to work on their weak areas.

Students can score good marks in math exams by regularly practicing the problems and with the help of free online math tutor it might help you in solving problems in different methods. You can also get math online help which makes you more easier to study well for your exams with different problem solving skills.

Article Source: http://EzineArticles.com/?expert=B._Jacob
http://EzineArticles.com/?Some-Useful-Ways-to-Get-Good-Scores-In-Math-Exams&id=7630772

Define Convex Polygon

Author: mathqa22

In polygon comprise no reflex angle, followed in it is made-up to be a convex polygon. Polygon is a plane, that type to be restricted in a closed path, composed of a restricted series of directly line element by a closed polygonal series. Now we study about define convex polygon.

Using online polygon is a plane type to be restricted in a closed path, composed of a restricted series of directly line element by a closed polygonal series.

Define convex polygon:

A polygon is absolutely convex if every interior position is definitely less than 180 quantities. Commonly, a polygon is definitely convex if each line division by two noncontiguous vertices of the polygon is exactingly internal to the polygon however on its endpoints. Each non part triangle is definitely convex.

A polygon is a 2-dimensional instance of the more general polytope in several quantities of proportions. The internal of the polygon is recognized its group. These fraction are known its edges, with the points where two edges obtain together are the polygon's curve.

Commonly, a polygon is definitely convex if each line division by two noncontiguous vertices of the polygon is exactingly internal to the polygon however on its endpoints

Properties of convex polygon:

A convex polygon is an easy that's within is a convex set. The properties of an easy polygon are all equal to convexity:

Each one interior angle is less than 180 degree.

Each one line segment among two vertices remains inside or on the maximum of the polygon.

Examples for define convex polygon:

Example 1 for define convex polygon:

How to solve area of the polygon learning the sides are (6,3) (9,3)(7,5)

area of the polygon learning the sides are (6,3) (9,3)(7,5)

Solution:

Step 1: the given sides are (6,3) (9,3)(7,5)

Step 2: A =     1/2((x_1y_2-x_2y_1)+(x_2y_3-x_3y_2)+.......(x_ny_1-x_1y_n))

Step 3: x1=6, y1=3, x2=9, y2=3, x3=7, y3=5,

Step 4:     A =1/2(18+45+35)-(27+21+30)

Step 5:         so area is A =10

Example 2 for define convex polygon:

How to solve area of the polygon learning the sides are (7,2) (7,4) (6,5)

area of the polygon learning the sides are (7,2) (7,4) (6,5)

Solution:

Step 1: the given sides are (7,2) (7,4) (6,5)

Step 2: A =     1/2((x_1y_2-x_2y_1)+(x_2y_3-x_3y_2)+.......(x_ny_1-x_1y_n))

Step 3: x1=7, y1=2, x2=7, y2=4, x3=6, y3=5,

Step 4:      A =1/2(28+35+12)-(14+24+35)

Step 5: so area is A =1

Check this icse syllabus 2013 awesome i recently used to see.

Example 3 for define convex polygon:

How to solve area of the polygon and  prepare the sides are (7,6)(6,4)(6,2)

area of the polygon and prepare the sides are (7,6)(6,4)(6,2)

Solution:

Step 1: the given sides are (7,6)(6,4)(6,2)

Step 2: A = 1/2((x_1y_2-x_2y_1)+(x_2y_3-x_3y_2)+.......(x_ny_1-x_1y_n))

Step 3: x1=7, y1=6, x2=6, y2= 4, x3=6, y3=2,

Step 4:    A =1/2(28+12+36)-(36+24+14)

Step 5:         so area is A = 1

Normally in geometry polygon mean a plane figure which is closed by a line. Here we are going to learn about name of all polygons. We will name the polygons based on their number of sides. We will see the name of the polygons.  Totally we are having three types of polygons that are regular, irregular and equilateral polygons.

Name of all polygons:

Here we are going to name all the polygons based on their number of sides.

If any polygons having 3 sides we can say it is Triangle.

If a polygons with 4 sides we will say it is a Quadrilateral.

If a polygon is having 5 sides it is known as Pentagon.

If a polygon is having 6 sides it is known as Hexagon.

If a polygon is having the number of sides 7 then we can say it is Heptagon.

If any polygon is having the number of sides 8 then we can say it is Octagon.

If a polygon is having the number of sides 9 it is known as Enneagon or Nonagon.

If any polygon is having the number of sides 10 it is known as Decagon.

Name of all polygons: Sides above 10

If the number of sides is 11 then it is known as Hendecagon.

If the number of sides is 12 then it is known as Dodecagon.

If the number of sides is 13 then it is Tridecagon.

If the number of sides is 14 then it is known as Tetdradecagon.

If the number of sides is 15 is known as pentadecagon.

If the number of sides is 16 then it is known as Hexadecagon.

The number of sides of the polygon is 17 it is known as Heptadecagon.

The number of sides is 18 then we can say it is a Octadecagon.

The number of sides is 19 then we can say it is a Enneadecagon.

The number of sides is 20 then we can say it is a Icosagon.

Number of sidesName of the polygon

20Icosagon

30Triacontagon

40Tetracontagon

50Pentacontagon

60Hexacontagon

70Heptaconatagon

80Octacontagon

90Enneacontagon

100Hectagon

1000Chiliagon

10000Myriagon

1000000Hecatommyriagon

Article Source: http://www.articlesbase.com/k-12-education-articles/define-convex-polygon-6615656.html

About the Author

Learn more on about Online Volume Conversion and its Examples. Between, if you have problem on these topics Testing Bias, Please share your comments.

High School Math Can Be Fun

High School Math Can Be Fun
By Lance Merlino

Mathematics is known as the language of physics, and it is a very important part of everyone's life. Mathematics is used in all facets of life. But, one of the problems with math is that it is termed as a difficult subject. Even before students learn the subject or even are exposed to it, they are filled with the presumption that math is very difficult. But, the fact of matter is that math is a very simple subject if it is taught properly, and if the student understands it from the basics. Here are a few tips to make high school math fun.

Diagrammatic Explanation

Figures and diagrams are used very often in mathematics. That is because describing a problem in terms of figures will give you a better understanding of the problem. In case a student does not follow the question with the diagram, the answer can be depicted diagrammatically, and can be explained to the student more clearly. Most of the times, this method works fabulously, with students who find math difficult. So, it is always important that a maths tutor is able to diagrammatically represent both a question and its answer.

Number Games

Using number games is a very old and effective ways of teaching math to students, who feel that math is hard. There are different types of number games that the maths tutor can come up with. For example, when teaching probability, you can use the example of having a set of colored balls in a box. You can work out how you want to convey the concept to the students. Similarly, there are other number games that you can choose from books, or devise on your own, to teach math to students.

Team Activities

There is also another way of teaching math, where you split the students into teams and set them up against each other. This will breed a competitive spirit among the participants, and motivate them to help each other out, to learn the concepts and be better than the other team. However, you will need a set of students, at least 4, for this type of approach.

Real Life Examples

You can also use real life examples to make students understand math concepts. This approach is a little tricky, as it involves a lot of homework for the maths tutor. But, once the tutor gets a hang of this approach, this is one of the most effective ways of teaching math.

Lance Merlino is an expert maths tutor with Maths Success and has a long list of math help success stories of science students.

Article Source: http://EzineArticles.com/?expert=Lance_Merlino
http://EzineArticles.com/?High-School-Math-Can-Be-Fun&id=7659860

How to Improve Your Math Skills

How to Improve Your Math Skills
By Amit Kothiyaal

Very few people are aware that mathematics is a branch of science; science enhances technology and technology makes life easier. In fact, if you compare our lifestyle to that of the previous generations, we can call ourselves luxurious. You have math to thank for that, because the right ingredients can be destructive when used in wrong amounts.

If that is not enough reason for you to want to improve your math skills, then let's zoom in to your personal life. Nothing in the market is for free. Aside from the basic addition, subtraction, multiplication, and division you perform in designating your budget, there are discounts to consider and promos to join. How many miles can the gas in your car tank take you? How many yards should the carpet you have to buy be? Did your secretary compute yesterday's expenditures correctly? How can you check? You see, there are plenty of reasons you should invest time in improving your math, because it will give you more confidence in dealing with numbers in daily activities. No, you don't have to throw yourself back in college or in review centers. There are simple and effective ways you can do this without the additional stress or expenses.

An Early Math Challenge

We're not sure where the wacky alarm clock ideas originated from (we bet the Japanese influenced them anyway) but that doesn't really matter as much as the fact that they work. One of these ideas is to require the sleepy-head to answer ten sets of equations in basic mathematics for the alarm to stop ringing. They can get annoying, especially if you are not a morning person, so just concentrate on its benefits. First and foremost, by the time you finish and silence resumes, your brain would be too awake to be seduced back to sleep.

Second, you will become more alert the longer you undergo this morning math surprise, and third, you will master the basics of math without even knowing it. Time pressure and noise will no longer be enough to distract you from coming up with the correct solution.

Download this kind of applications and install them in your mobile phone. Make sure your thread of patience is long enough before you attempt this. Otherwise, your poor phone might end up on the floor, crushed to pieces.

The Advantages of Lending a Hand

The next time your son or daughter asks you to help them with their math homework, say yes and give it your best shot. Learning more about math is never a loss, and in this instance, your interest in numbers may influence your child to do better at school.

Teenagers can offer after-school tutoring for free or for a certain amount of money. Getting paid for assisting others in math education can be an effective motivation to study it further. You wouldn't want to teach others the wrong things, wouldn't you? The people you teach may also add to your current bank of knowledge. Math is like a maze, there can be more ways than one to get to your destination.

A Virtual Learning Experience

Math help need not be boring, and the first two examples are proofs of that. The worldwide web is anything but dull. Online mathematics courses create a suitable playground for modern minds. Lessons are commonly presented in the form of game, puzzles, and trivia, keeping users easily engaged. Similar to the approach of the first examples, your attention is diverted from improving your math skills to interacting with an entirely different and enjoyable game.

During your free time, you can boot up your laptop or bring out your mobile gadgets to access these math applications. Killing time has never been this fruitful.

The Brain is a Powerful Tool

A computer system is patterned after the human brain. If you think the former is impressive, then you should be in awe of the latter. But to maximize your brain's greatness, you have to exercise it. Avoid using calculators when doing your grocery of summing up your monthly bills. Calculate mentally whenever you can, and bring out your gadgets only to check whether you are correct.

This practice makes you less reliant on tools and more confident in your skills. It also saves time, energy, and space in your bag. The next time you see numbers, get excited and start jogging your brain. You will be shocked by the results.

The author loves writing on various subjects like Math, English and Science. He also writes about the advantages of online math courses, and how virtual Math lessons can act as an effective medium to learn the trickiest concepts.

Article Source: http://EzineArticles.com/?expert=Amit_Kothiyaal
http://EzineArticles.com/?How-to-Improve-Your-Math-Skills&id=7640930

Online Basic Geometry Definitions

Author: Omkar

Introduction to online basic geometry definitions tutor:

In this article online basic geometry definitions tutor,we will learn some important geometry definitions they are necessary to understand geometry concept.Those basic geometry definitions are used to design a graph with the assistance of those terms. Tutor will teach to individual and guide them to get the solution for problems through some websites via online. Online is a tool for self-learning from websites.

Basic definitions- online basic geometry definitions tutor

Supplementary angles:

We can call any two angles as supplementary angles,if the sum up of them should be 180°

Complementary angles:

We can call any two angles as complementary angles,if the sum up of them should be 90°

Acute triangle:

An acute triangle means a triangle in which all three angles should be less than 90°.

Obtuse triangle:

Obtuse triangle means one type of triangle in this one angle must be greater than 90°.

Right angle triangle:

A right angle triangle means one type of triangle in which one angle must be a right (90°) angle.

Triangle Inequality:

The triangle inequality means the addition of any two side should be greater than the third side

Scalene Triangle:

A scalene triangle means a triangle with three different unequal length of side.

some more definitions- online basic geometry definitions tutor

Centroid:

The centroid means a point in which three lines will meet each other. This point is a center point of a triangle. If we cut a triangle corresponds to that center we will get three equal parts.

Circle:

In circle the distance between the center and to any point present in the outer line of a circle is same.

Radius:

Radius of a circle is the distance between the circle's center and any point present on the circle.

Circumcenter:

In a triangle three perpendicular line drawn from the three sides bisect each other . That point is called as circumcenter.From this center point we can draw a circle

Congruent:

Two figures are said to congruent when all the parameters should be same interms of length and angles.

Altitude:

An altitude means a line connecting a vertex to the opposite side.

Vertex:

Vertex means a point.

Transversal:

A transversal means a line which passes through two another lines there is a no issue that should be parallel.

Point:

A point indicates a single location

Plane:

Plane is a flat, two-dimensional object one.

Quadrilateral:

Quadrilateral is defined as a polygon and has exactly 4 sides.

Trapezoid:

A trapezoid means a quadrilateral which contain one pair of opposite side they should be parallel to each other.

Polygon:

A polygon means a two-dimensional geometric object.It is made up of a straight line segment those segments touches at the ends.

Rectangle:

Rectangle means a quadrilateral and should has 4 right angle.

These are the few terms for online basic geometry definitions tutor

Article Source: http://www.articlesbase.com/k-12-education-articles/online-basic-geometry-definitions-6615588.html

About the Author

Comprehend more on about Graphing Linear Equations and its Circumstances. Between, if you have problem on these topics acute scalene triangle Please share your views here by commenting.

Types of Pentagon

Author: nitin.p070

A pentagon is a closed two dimensional figure that is the union of line segments in a plane. A pentagon has the five sides and five angles. The internal angles in a simple pentagon total 540°. A pentagram is an example of a self-intersecting pentagon. A regular pentagon has five Edges and five vertices. Internal angle of a regular pentagon is 108 degree. There are two types of pentagons : concave pentagon and convex pentagon.

In geometry an equilateral pentagon is a polygon with five sides of equal length. Its five internal angles, in turn, can take a range of sets of values, thus permitting it to form a family of pentagons. In contrast, the regular pentagon is unique, because it is equilateral and moreover its five angles are equal.
Four intersecting equal circles arranged in a closed chain are sufficient to determine an equilateral pentagon. Each circle's center is one of four vertices of the pentagon. The remain vertex is determined by the intersection of the first and the last circle of the chain.

It is possible to describe any equilateral pentagon with only two angles a and ß with a = ß provided the fourth angle (d) is the smallest of the rest of the angles. Thus the general equilateral pentagon can be regarded as a bivariate function f(\alpha,\beta) where the rest of the angles can be obtained by using trigonometric relations. The equilateral pentagon described in this manner will be unique up to a rotation in the plane.

Types of Pentagon : Concave and Convex Pentagon:

Concave pentagon:

It is a five sided polygon. At least one interior angle is greater than 180 degrees.

This causes some of the vertices of the pentagon to points towards the center.

An alternate definition exists a line that will cut the polygon in 4 or more places.

The twelve concave pentagons can be get together to make a concave dodecahedron.

Convex pentagon:

It is a shape with 180degrees or less.

The regular pentagon is the example of the convex pentagon.

Let us see regular pentagon in detail.

Express your views on the topic 9th cbse sample papers 2011 by commenting on articles.

Types of Pentagon : Regular Pentagon

A shape with five equal sides and five equal angles are called as Regular Pentagon.

Properties of Regular Pentagon:

• It has five equal sides
• It has five equal angles
• It has five lines of symmetry

Angle of a Regular pentagon:

Exterior angle of any polygon is 360° and hence the exterior angle of a regular pentagon is 360°.

Regular pentagon has five sides so each exterior angle measures (360/5) = 72°.

Interior angle of a polygon is calculated by using the formula,
n - 2 (180)

Where n =number of sides.

Where n =number of sides.

Here for pentagon interior angle = (5 - 2) 180 = 540°.

For regular pentagon each side interior angle = 540 / 5 = 108°.

Area of any regular polygon is:

A = 5t2 tan (54) / 4

Derivation of the diagonal length formula:

D = T * (1+v5) / 2

Article Source: http://www.articlesbase.com/online-education-articles/types-of-pentagon-6278397.html

About the Author

Understand more on about the How to find the Center of a Circle, and its Illustrations. Between, if you have issue on these Geometry Angles keep verifying my content i will try to help you. Please discuss your feedback.

Pascal's Triangle and Polygonal Numbers

Pascal's Triangle and Polygonal Numbers
By Alec L Shute

Polygonal numbers are a kind of general set of patters, a sequence of sequences. Common examples include triangle and square numbers, but we can also have less well known sequences such as pentagonal, hexagonal, heptagonal etc. numbers, all of which are closely linked with Pascal's triangle.

First I will explain how all of these sequences can be formed. Triangle numbers are made from adding consective integers, or adding one more each time. The first few terms are 1,3,6,10,15,21,28,36,45,55. To get to the next term, you add 2 then 3, then 4 and so on.

The square numbers are usually thought of as the sequence made from multiplying numbers by themselves, for example the sixth square is 6 x 6 = 36. However, for the purpose of linking them to triangle numbers and the other polygonal sequences, we shall consider them in a slightly different way. Square numbers can be made by adding consecutive odd numbers - the sequence 1,4,9,16,25,36,49... has differences of 3,5,7,9,11,13... , which are the odd numbers.

Continuing this idea, the pentagonal sequence is 1,5,12,22,35,51... which have a difference of 4,7,10,13,16... , which are the multiples of 3 add 1, and the hexagonal numbers are 1,6,15,28,45,66... , which have a difference of 5,9,13,17,21... , which are the multiples of 4 add 1 (the hexagonal sequence also turns out to be every other triangle number). So an n-gonal number will have a first term of 1, then differences corresponding to multiples of n-2 add 1.

Now we can link all this in with Pascal's triangle. The triangle numbers 1,3,6,10,15... are famously found in the third diagonal in of Pascal's triangle, as shown in bold below:

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 21 15 6 1

The square numbers (or any other polygonal sequences for that matter), however, are much harder to spot. The trick is to look in the same diagonal as we just obtained the triangle numbers from, but as they themselves don't appear there, we have to do a bit of adding to get them. The square numbers can be found by taking the sums of the consecutive values in this diagonal. So we get

(0) + 1 = 1

1 + 3 = 4

3 + 6 = 9

6 + 10 = 16 etc.

We apply a very similar process to create any polygonal sequence from Pascal's triangle. For the pentagonal numbers, we must multiply the first number by 2:

2 x (0) + 1 = 1

2 x 1 + 3 = 5

2 x 3 + 6 = 12

2 x 6 + 10 = 22 etc.

For hexagonal numbers, we multiply the first value in the sum by 3, for heptagonal numbers we multiply the first value by 4 and so on. This shows how we can create any polygonal number from Pascal's Triangle. This just goes to show how many patterns can be explored in Pascal's Triangle, as we have created an infinitely many sequences just from a single diagonal! For more information on some of the amazing patterns and properties of Pascal's Triangle, as well as a visual representation of the polygonal numbers, you are welcome to visit my site listed in the links below.

Pascal's Triangle

Pascal's Triangle

Article Source: http://EzineArticles.com/?expert=Alec_L_Shute
http://EzineArticles.com/?Pascals-Triangle-and-Polygonal-Numbers&id=7625795