Pre algebra review tests
Author: Matthew DavidPre algebra review tests
Introduction to pre algebra review tests:-
In this article we are learning about the pre algebra review tests the concept. Algebra is cluster of mathematics and it process on the pre algebra review tests. Pre algebra review tests cover the four basic operations such as addition, subtraction, multiplication and division. The most important expression of pre algebra review tests is variable, constant coefficient, exponent, word and expression. Pre algebra review tests beside numeral we use symbol and alphabet in place of unknown number to make a statement. Hence, pre algebra review tests related problem shown below.
Pre-algebra is division of mathematics is that replacement letters for numbers. An algebraic equation is stand for the scale, what is finished on the one side of a scale with a number is also completed to the other side of the scale. This type of mathematics is called algebra. In this article we shall discuss about how to do pre-algebra problems with some examples.
Sample problem for how to do pre algebra:
Problem 1:
Find the value of given fraction numbers `2/3 ` + `1/3`
Solution:
In the proper fraction a denominator values are same. So we are directly added or subtract the numerator values.
Step 1: In here the denominator values are same.
Step 2: Add the numerator values and place over the same denominator values.
`2/3 ` + `1/3`= `(2 + 1)/3`
= `3 / 3`
Step 3: Now we are simplify the fraction values
= 1
Problem 2:
Solve the given values using simple arithmetic operations 9 + (7 * 2)
Solution:
We are going to find the value of given numerical values.
In the first step we are going to multiply the values 7 and 2, we get
7 x 2 = 14
In the next step add the value 14 and 9, we get
9 + 14 = 23
The sum value of the given numerical value is 23.
Pre-algebra Problem 3:
Evaluate the given problem and find the sum value 6 - `(8 / 2^2)`
Solution:
We are going to find the value of given numbers.
In the first step we are going to find the value of 8 and 22, we get
`8 / 2^2 ` =` 8 / 4`
= 2
In the next step we are subtract the two terms 6 and 2 we get
6 – 2 = 4
The sum value of the given terms is 4.
Problem 4:
Solve the given equation X – 5 = 8.
Solution:
We are going to find the x value of the given equation. In the first step move -5 into the right side of the equation, we get
X = 8 + 5
X = 13
We get x value as 13.
Pre algebra review tests questions:-
1. Write b. b. b. b. b. a. a. a in exponential form.
2. Evaluate `x^4.y^2` when x = 2 and y = 5
3. What is the square of 13?
4. Find the quotient of 3270 and 32.
5. a. Find 0/16 b. Find 16/16 c. Find 16/0 d. Find 16/1
6. Simplify: 8+`6^2` +8÷2
7. Simplify: 20 + 4(5)
8. Simplify: 43+6·12-6÷2
9. Find the opposite of –6.
10. Find the opposite of 12.
11. Write the expression –4-(-3) in words.
12. Simplify: -(9)
13. Add.-31+75+ (-69)
14. What is 22 added to –19?
15. Evaluate the expression – a + b-c, when a = -6, b =4, and c = -3.
16. Use the Inverse Property of Addition to complete the statement_____+12=0
17. What is –21 decreased by –13?
18. Simplify. 13+ (-9)-18-(-5)-3+14
19. Evaluate yx--, when x = -12 and y = -23.
20. Is –11 a solution to 5-(-x) =16?
21. Find the temperature after a rise of 22° F from -31°F.
22. Solve -7+x=-5
23. Solve -4n=56.
24. The difference between a number and seven is twenty-eight. Find the number.
pre algebra review tests answer keys:-
1. `a^3b^5`
2. 400
3. 169
4. 102 R 6
5. a. 0 b. 1 c. undefined d. 16
6. 48
7. 40
8. 13 9. 54
9. 6
10. -12
11. negative four minus negative three
12. 3
13. –25
14. 3
15. 13
16. –12
17. –8
18. 2
19 35
20. NO
21. -9° F
22. x = 2
23. n = -14
24. x = 35.
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About the AuthorBetween, if you have problem on these topics Solving Quadratic Equations by Completing the Square, please browse expert math related websites for more help on Find the Median and different math topic.
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